1. Electric Charges and Fields
easy

$5\,\mu C$ के बिन्दु आवेश से $80$ सेमी. दूर किसी बिन्दु पर विद्युत क्षेत्र की तीव्रता होगी

A

$8 \times {10^4}\,N/C$

B

$7 \times {10^4}\,N/C$

C

$5 \times {10^4}\,N/C$

D

$4 \times {10^4}\,N/C$

Solution

$E = 9 \times {10^9}.\frac{Q}{{{r^2}}}$$ = 9 \times {10^9} \times \frac{{5 \times {{10}^{ – 6}}}}{{{{(0.8)}^2}}} = 7 \times {10^4}\,N/C$

Standard 12
Physics

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