1.Units, Dimensions and Measurement
easy

Error in the measurement of radius of a sphere is $0.2\%$. The error in the calculated value of its volume is  ......... $\%$

A

$0.2$

B

$0.6$

C

$0.4$

D

$0.8$

Solution

${\text{V}} = \frac{{\text{4}}}{{\text{3}}}\pi {r^3}$

$ = \frac{{\Delta V}}{V} \times 100 = 3\left[ {\frac{{\Delta r}}{r} \times 100} \right] = 3 \times 0.2= 0.6\% $

Standard 11
Physics

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