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1.Units, Dimensions and Measurement
easy
Error in the measurement of radius of a sphere is $0.2\%$. The error in the calculated value of its volume is ......... $\%$
A
$0.2$
B
$0.6$
C
$0.4$
D
$0.8$
Solution
${\text{V}} = \frac{{\text{4}}}{{\text{3}}}\pi {r^3}$
$ = \frac{{\Delta V}}{V} \times 100 = 3\left[ {\frac{{\Delta r}}{r} \times 100} \right] = 3 \times 0.2= 0.6\% $
Standard 11
Physics