Evaluate $\Delta=\left|\begin{array}{lll}3 & 2 & 3 \\ 2 & 2 & 3 \\ 3 & 2 & 3\end{array}\right|$
Evaluate $\Delta=\left|\begin{array}{lll}3 & 2 & 3 \\ 2 & 2 & 3 \\ 3 & 2 & 3\end{array}\right|$
Solution Expanding along first row, we get
$\begin{aligned}
\Delta &=3(6-6)-2(6-9)+3(4-6) \\
&=0-2(-3)+3(-2)=6-6=0
\end{aligned}$
Here $R_{1}$ and $R_{3}$ are identical.
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