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8. Introduction to Trigonometry
easy
કિંમત શોધો : $\frac{\tan 65^{\circ}}{\cot 25^{\circ}}$
A
$0$
B
$2$
C
$5$
D
$1$
Solution
આપણે જાણીએ છીએ કે,
$\cot A=\tan \left(90^{\circ}- A \right)$
માટે,$\cot 25^{\circ}=\tan \left(90^{\circ}-25^{\circ}\right)=\tan 65^{\circ}$
એટલે કે, $\frac{\tan 65^{\circ}}{\cot 25^{\circ}}=\frac{\tan 65^{\circ}}{\tan 65^{\circ}}=1$
Standard 10
Mathematics
