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8. Introduction to Trigonometry
easy
निम्नलिखित का मान निकालिए:
$\cos 48^{\circ}-\sin 42^{\circ}$
A
$0$
B
$1$
C
$-1$
D
$0.5$
Solution
$\cos 48^{\circ}-\sin 42^{\circ}=\cos \left(90^{\circ}-42^{\circ}\right)-\sin 42^{\circ}$
$=\sin 42^{\circ}-\sin 42^{\circ}$
$=0$
Standard 10
Mathematics