8. Introduction to Trigonometry
easy

Evaluate:

$\cos 48^{\circ}-\sin 42^{\circ}$

A

$0$

B

$1$

C

$-1$

D

$0.5$

Solution

$\cos 48^{\circ}-\sin 42^{\circ}=\cos \left(90^{\circ}-42^{\circ}\right)-\sin 42^{\circ}$

$=\sin 42^{\circ}-\sin 42^{\circ}$

$=0$

Standard 10
Mathematics

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