Explain electric field and also electric field by point charge.
Suppose, charge $\mathrm{Q}$ is placed at origin ' $\mathrm{O}^{\prime}$ in free space. If another charge $q$ is placed at distance $r$ at point $\mathrm{P}(\mathrm{OP}=r)$, then Coulomb force acts on $q$.
$\overrightarrow{\mathrm{F}}=\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{\mathrm{Q} q}{r^{2}} \hat{r}$
If $q=1 \mathrm{C}$, then force acting on unit charge is called electric field $\mathrm{E}$.
$\therefore \frac{\overrightarrow{\mathrm{F}}}{q}=\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{\mathrm{Q}}{r^{2}} \hat{r}$ $\therefore \overrightarrow{\mathrm{E}}=\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{\mathrm{Q}}{r^{2}} \hat{r}$ or $\mathrm{E}=\frac{k \mathrm{Q}}{r^{2}}$
Definition of electric field: 'The region around the charge in which the effect of electric charge is prevailing is called the electric field of the charge.'
Electric field $\overrightarrow{\mathrm{E}}$ is also called electric field intensity. Force acting on charge $q$ of position vector $\vec{r}$ is $\overrightarrow{\mathrm{F}}(\vec{r})=q \overrightarrow{\mathrm{E}}(\vec{r})$
Electric field $\vec{E}$ is also called electric field intensity.
Definition of Electric field : 'The force acting on a unit positive charge at a given point in an electric field of a point charge of the system at charge is called the electric field or intensity of electric field $\overrightarrow{\mathrm{E}}$ at that point.
SI unit of electric field intensity is $\mathrm{NC}^{-1}$ or $\mathrm{Vm}^{-1}$ and dimensional formula is $\left[\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-3} \mathrm{~A}^{-1}\right]$.
Six charges, three positive and three negative of equal magnitude are to be placed at the vertices of a regular hexagon such that the electric field at $O$ is double the electric field when only one positive charge of same magnitude is placed at $R$. Which of the following arrangements of charges is possible for $P,\,Q,\,R,\,S,\,T,\,$ and $U$ respectively
The tiny ball at the end of the thread shown in figure has a mass of $0.5 \, g$ and is placed in a horizontal electric field of intensity $500\, N/C$. It is in equilibrium in the position shown. The magnitude and sign of the charge on the ball is .....$\mu C$
Two point charges $Q_1, Q_2$ are fixed at $x = 0$ and $x = a$. Assuming that field strength is positive in the direction coinciding with the positive direction of $x$, then, which following option will be correct ?
Two point charges $q_1\,(\sqrt {10}\,\,\mu C)$ and $q_2\,(-25\,\,\mu C)$ are placed on the $x-$ axis at $x = 1\,m$ and $x = 4\,m$ respectively. The electric field (in $V/m$ ) at a point $y = 3\,m$ on $y-$ axis is, [ take ${\mkern 1mu} {\mkern 1mu} \frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}{\mkern 1mu} {\mkern 1mu} N{m^2}{C^{ - 2}}{\rm{ }}$ ]
As shown in the figure, a particle A of mass $2\,m$ and carrying charge $q$ is connected by a light rigid rod of length $L$ to another particle $B$ of mass $m$ and carrying charge $-q.$ The system is placed in an electric field $\vec E$ . The electric force on a charge $q$ in an electric field $\vec E$ is $\vec F = q \vec E $ . After the system settles into equilibrium, one particle is given a small push in the transverse direction so that the rod makes a small angle $\theta_0$ with the electric field. Find maximum tension in the rod.