Explain the analytical method for vector addition.
It is much easier to add vectors by combining their respective components.
Consider two vectors $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ in $x y$-plane with components $\mathrm{A}_{x}, \mathrm{~A}_{y}$ and $\mathrm{B}_{x}, \mathrm{~B}_{y}$
$\therefore \overrightarrow{\mathrm{A}}=\mathrm{A}_{x} \hat{i}+\mathrm{A}_{y} \hat{j}$
$\therefore \overrightarrow{\mathrm{B}}=\mathrm{B}_{x} \hat{i}+\mathrm{B}_{y} \hat{j}$
Let $\overrightarrow{\mathrm{R}}$ be their sum.
$\overrightarrow{\mathrm{R}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}$
$\therefore \overrightarrow{\mathrm{R}}=\left(\mathrm{A}_{x} \hat{i}+\mathrm{A}_{y} \hat{j}\right)+\left(\mathrm{B}_{x} \hat{i}+\mathrm{B}_{y} \hat{j}\right)$
Since vectors obey the commutative and associative laws.
$\therefore \overrightarrow{\mathrm{R}}=\left(\mathrm{A}_{x}+\mathrm{B}_{x}\right) \hat{i}+\left(\mathrm{A}_{y}+\mathrm{B}_{y}\right) \hat{j}$
$\therefore \overrightarrow{\mathrm{R}}=\mathrm{R}_{x} \hat{i}+\mathrm{R}_{y} \hat{j}$
$\mathrm{R}_{x}=\mathrm{A}_{x}+\mathrm{B}_{x}$
$\mathrm{R}_{y}=\mathrm{A}_{y}+\mathrm{B}_{y}$
Thus, each component of the resultant vector $\overrightarrow{\mathrm{R}}$ is the sum of the corresponding components of $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$.
It is much easier to add vectors by combining their respective components.
Consider two vectors $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ in $x y$-plane with components $\mathrm{A}_{x}, \mathrm{~A}_{y}$ and $\mathrm{B}_{x}, \mathrm{~B}_{y}$
$\therefore \overrightarrow{\mathrm{A}}=\mathrm{A}_{x} \hat{i}+\mathrm{A}_{y} \hat{j}$
$\therefore \overrightarrow{\mathrm{B}}=\mathrm{B}_{x} \hat{i}+\mathrm{B}_{y} \hat{j}$
Let $\overrightarrow{\mathrm{R}}$ be their sum.
$\overrightarrow{\mathrm{R}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}$
$\therefore \overrightarrow{\mathrm{R}}=\left(\mathrm{A}_{x} \hat{i}+\mathrm{A}_{y} \hat{j}\right)+\left(\mathrm{B}_{x} \hat{i}+\mathrm{B}_{y} \hat{j}\right)$
Since vectors obey the commutative and associative laws.
$\therefore \overrightarrow{\mathrm{R}}=\left(\mathrm{A}_{x}+\mathrm{B}_{x}\right) \hat{i}+\left(\mathrm{A}_{y}+\mathrm{B}_{y}\right) \hat{j}$
$\therefore \overrightarrow{\mathrm{R}}=\mathrm{R}_{x} \hat{i}+\mathrm{R}_{y} \hat{j}$
$\mathrm{R}_{x}=\mathrm{A}_{x}+\mathrm{B}_{x}$
$\mathrm{R}_{y}=\mathrm{A}_{y}+\mathrm{B}_{y}$
Thus, each component of the resultant vector $\overrightarrow{\mathrm{R}}$ is the sum of the corresponding components of $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$
Which of the following relations is true for two unit vectors $\hat{ A }$ and $\hat{ B }$ making an angle $\theta$ to each other$?$
If the sum of two unit vectors is a unit vector, then magnitude of difference is
Explain the parallelogram method for vector addition. Also explain that this is comparable to triangle method.