14.Probability
easy

નીચે આપેલા કોષ્ટકમાં ખાલી જગ્યા ભરો : 

$P(A)$ $P(B)$ $P(A \cap B)$ $P (A \cup B)$
$\frac {1}{3}$ $\frac {1}{5}$ $\frac {1}{15}$  ........

Option A
Option B
Option C
Option D

Solution

$P ( A )=\frac{1}{3}$,  $P ( B )=\frac{1}{5}$,  $P ( A \cap B )=\frac{1}{15}$

Here,

We know that $P ( A \cup B )= P ( A )+ P ( B )- P ( A \cap B )$

$\therefore P(A \cup B)$ $=\frac{1}{3}+\frac{1}{5}+\frac{1}{15}$ $=\frac{5+3-1}{15}$ $=\frac{7}{15}$

Standard 11
Mathematics

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