ખાલી જગ્યા પૂરો : ${{\mathop{\rm U}\nolimits} ^\prime } \cap A =  \ldots $

Vedclass pdf generator app on play store
Vedclass iOS app on app store

$U^{\prime} \cap A=\varnothing \cap A=\varnothing$

$\therefore U^{\prime} \cap A=\varnothing$

Similar Questions

જો $U =\{1,2,3,4,5,6,7,8,9\}, A =\{2,4,6,8\}$ અને $B =\{2,3,5,7\}$ હોય, તો $(A \cap B)^{\prime}=A^{\prime} \cup B^{\prime}$ ચકાસો.

જો બે ગણો $A$ અને $B$ હોય ,તો $(A \cap B)'$ મેળવો.

$U=\{1,2,3,4,5,6,7,8,9\}, A=\{1,2,3,4\}, B=\{2,4,6,8\}$ અને $C=\{3,4,5,6\}$ છે. નીચેના ગણ શોધો : $\left(A^{\prime}\right)^{\prime}$

જો  $U = \{ 1,\,2,\,3,\,4,\,5,\,6,\,7,\,8,\,9,\,10\} $, $A = \{ 1,\,2,\,5\} ,\,B = \{ 6,\,7\} $, તો  $A \cap B'$ મેળવો.

$U=\{1,2,3,4,5,6\}, A=\{2,3\}$ અને $B=\{3,4,5\}.$ $A^{\prime}, B^{\prime}, A^{\prime} \cap B^{\prime}, A \cup B$ શોધો અને તે પરથી બતાવો કે $(A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}.$