4. Linear Equations in Two Variables
easy

Find four different solutions of the equation $x + 2y = 6.$

Option A
Option B
Option C
Option D

Solution

By inspection, $x=2,\, y=2$ is a solution because for $x=2,\, y=2$

$x+2 y=2+4=6$

Now, let us choose $x = 0$. With this value of x, the given equation reduces to $2y = 6$ which has the unique solution $y = 3$. So $x = 0$, $y = 3$ is also a solution of $x + 2y = 6$. Similarly, taking $y = 0$, the given equation reduces to $x = 6$. So, $x = 6$, $y = 0$ is a solution of $x + 2y = 6$ as well. Finally, let us take $y = 1$. The given equation now reduces to $x + 2 = 6$, whose solution is given by $x = 4$. Therefore, $(4,\, 1)$ is also a solution of the given equation. So four of the infinitely many solutions of the given equation are :

$(2,\,2)$, $(0,\,3)$, $(6,\,0) $ and $ (4,\,1)$

Standard 9
Mathematics

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