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8. Sequences and Series
easy
Find the $7^{\text {th }}$ term in the following sequence whose $n^{\text {th }}$ term is $a_{n}=\frac{n^{2}}{2^{n}}$
A
$\frac{49}{128}$
B
$\frac{49}{128}$
C
$\frac{49}{128}$
D
$\frac{49}{128}$
Solution
Substituting $n=7,$ we obtain
$a_{7}=\frac{7^{2}}{2^{7}}=\frac{49}{128}$
Standard 11
Mathematics