7^{text {th }} term in following sequence whose n^{text {th }} term is a_{n}=frac{n^{2}}{2^{n}}

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8. Sequences and Series

easy

Find the $7^{\text {th }}$ term in the following sequence whose $n^{\text {th }}$ term is $a_{n}=\frac{n^{2}}{2^{n}}$

A

$\frac{49}{128}$

B

$\frac{49}{128}$

C

$\frac{49}{128}$

D

$\frac{49}{128}$

Solution

Substituting $n=7,$ we obtain

$a_{7}=\frac{7^{2}}{2^{7}}=\frac{49}{128}$

Standard 11

Mathematics

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