A physical quantity Q is found to depend on q | vedclass

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Question

$ \mathrm{Q}=\frac{\mathrm{a}^4 \mathrm{~b}^3}{\mathrm{c}^2} $

$ \frac{\Delta \mathrm{Q}}{\mathrm{Q}}=4 \frac{\Delta \mathrm{a}}{\mathrm{a}}+3 \fra

Vedclass · Accepted Answer

$34 \%$

Vedclass · Answer

$ \mathrm{Q}=\frac{\mathrm{a}^4 \mathrm{~b}^3}{\mathrm{c}^2} $

$ \frac{\Delta \mathrm{Q}}{\mathrm{Q}}=4 \frac{\Delta \mathrm{a}}{\mathrm{a}}+3 \frac{\Delta \mathrm{b}}{\mathrm{b}}+2 \frac{\Delta \mathrm{c}}{\mathrm{c}} $

$ \frac{\Delta \mathrm{Q}}{\mathrm{Q}} 	imes 100=4\left(\frac{\Delta \mathrm{a}}{\mathrm{a}} 	imes 100ight)+3\left(\frac{\Delta \mathrm{b}}{\mathrm{b}} 	imes 100ight)+2\left(\frac{\Delta \mathrm{c}}{\mathrm{c}} 	imes 100ight) $

$ \% 	ext { error in } \mathrm{Q}=4 	imes 3 \%+3 	imes 4 \%+2 	imes 5 \% $

$=12 \%+12 \%+10 \% $

$=34 \%$

A physical quantity $Q$ is found to depend on quantities $a, b, c$ by the relation $Q=\frac{a^4 b^3}{c^2}$. The percentage error in $a$, $b$ and $c$ are $3 \%, 4 \%$ and $5 \%$ respectively. Then, the percentage error in $\mathrm{Q}$ is :

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