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Find the values of $a, \,b,\, c,$ and $d$ from the following equation:
$\left[\begin{array}{cc}
2 a+b & a-2 b \\
5 c-d & 4 c+3 d
\end{array}\right]=\left[\begin{array}{cc}
4 & -3 \\
11 & 24
\end{array}\right]$
$a=1$, $b=2$, $c=3$, $d=4$
$a=1$, $b=4$, $c=3$, $d=4$
$a=1$, $b=2$, $c=5$, $d=4$
$a=8$, $b=2$, $c=3$, $d=4$
Solution
Solution By equality of two matrices, equating the corresponding elements, we get
$\begin{array}{ll}
2 a+b=4 & 5 c-d=11 \\
a-2 b=-3 & 4 c+3 d=24
\end{array}$
Solving these equations, we get
$a=1$, $b=2$, $c=3$ and $d=4$
Similar Questions
A manufacturer produces three products $x,\, y,\, z$ which he sells in two markets. Annual sales are indicated below:
Market | $x$ | $y$ | $z$ |
$I$ | $10,000$ | $2,000$ | $18,000$ |
$II$ | $6,000$ | $20,000$ | $8,000$ |
If unit sale prices of $x, \,y$ and $z$ are Rs. $2.50$, Rs. $1.50$ and Rs. $1.00,$ respectively, find the total revenue in each market with the help of matrix algebra.