For a concentrated solution of a weak electrolyte ( $K _{ eq }=$ equilibrium constant) $A _2 B _3$ of concentration ' $c$ ', the degree of dissociation " $\alpha$ ' is
$\left(\frac{ K _{ eq }}{108 c ^4}\right)^{\frac{1}{5}}$
$\left(\frac{ K _{ eq }}{6 c ^5}\right)^{\frac{1}{5}}$
$\left(\frac{K_{e q}}{5 c^4}\right)^{\frac{1}{5}}$
$\left(\frac{ K _{ eq }}{25 c ^2}\right)^{\frac{1}{5}}$
Explain a general step-wise approach to evaluate the $pH$ of the weak electrolyte.
Write characteristics and uses of ${K_a}$ value.
A monoprotic acid in a $0.1\,\,M$ solution ionizes to $0.001\%$. Its ionisation constant is
At $25\,^oC$, the dissociation constant of $CH_3COOH$ and $NH_4OH$ in aqueous solution are almost the same. The $pH$ of a solution $0.01\, N\, CH_3COOH$ is $4.0$ at $25\,^oC$. The $pH$ of $0.01\, N\, NH_4OH$ solution at the same temperature would be
What is the $ pH$ of $0.01\, M$ glycine solution? For glycine, $K{a_1} = 4.5 \times {10^{ - 3}}$ and $K{a_2} = 1.7 \times {10^{ - 10}}$ at $298 \,K$