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6-2.Equilibrium-II (Ionic Equilibrium)
medium
For a concentrated solution of a weak electrolyte ( $K _{ eq }=$ equilibrium constant) $A _2 B _3$ of concentration ' $c$ ', the degree of dissociation " $\alpha$ ' is
A
$\left(\frac{ K _{ eq }}{108 c ^4}\right)^{\frac{1}{5}}$
B
$\left(\frac{ K _{ eq }}{6 c ^5}\right)^{\frac{1}{5}}$
C
$\left(\frac{K_{e q}}{5 c^4}\right)^{\frac{1}{5}}$
D
$\left(\frac{ K _{ eq }}{25 c ^2}\right)^{\frac{1}{5}}$
(JEE MAIN-2023)
Solution
$A _2 B _3 \text { (aq.) } \rightleftharpoons 2 A _{\text {(aq.) }}^{3+}+3 B _{\text {(aq) }}^{2-}$
$K _{ eq }=\frac{\left[ A ^{3+}\right]^2\left[ B ^{2-}\right]^3}{\left[ A _2 B _3\right]}=\frac{4 c ^2 \alpha^2 \times 27 c ^3 \alpha^3}{ c (1-\alpha)}$
$K _{ eq }=\frac{108 c ^5 \alpha^5}{ c } \alpha=\left(\frac{ K _{ eq }}{108 c ^4}\right)^{\frac{1}{5}}$
Standard 11
Chemistry
