7.Gravitation
easy

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

A

$2$

B

$\frac{1}{2}$

C

$\frac{1}{{\sqrt 2 }}$

D

$\sqrt 2 $

(AIPMT-2005)

Solution

(b) For a moving satellite kinetic energy $ = \frac{{GMm}}{{2r}}$
Potential energy $ = \frac{{ – GMm}}{r}$
$\frac{{{\rm{Kinetic}}\,{\rm{energy}}}}{{{\rm{Potential}}\,{\rm{energy}}}} = \frac{1}{2}$

Standard 11
Physics

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