For any two independent events {E₁} and {E₂}, P,{ ({E₁} cup {E₂}) cap ({bar E₁} cap {bar E

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14.Probability

easy

For any two independent events ${E_1}$ and ${E_2},$ $P\,\{ ({E_1} \cup {E_2}) \cap ({\bar E_1} \cap {\bar E_2})\} $ is

$ < \frac{1}{4}$

$ > \frac{1}{4}$

$ \ge \frac{1}{2}$

None of these

(IIT-1991)

Solution

(a) Since $\overline {{E_1}} \cap \overline {{E_2}} = \overline {{E_1} \cup {E_2}} $ and $({E_1} \cup {E_2}) \cap (\overline {{E_1} \cup {E_2}} ) = \phi $

$P\,\{ ({E_1} \cup {E_2}) \cap (\overline {{E_1}} \cap \overline {{E_2}} )\} = P(\phi ) = 0 < \frac{1}{4}$.

Standard 11

Mathematics

For the three events $A, B$ and $C, P$ (exactly one of the events $A$ or $B$ occurs) = $P$ (exactly one of the events $B$ or $C$ occurs)= $P$ (exactly one of the events $C$ or $A$ occurs)= $p$ and $P$ (all the three events occur simultaneously) $ = {p^2},$ where $0 < p < 1/2$. Then the probability of at least one of the three events $A, B$ and $C$ occurring is

hard

(IIT-1996)

If ${A_1},\,{A_2},…{A_n}$ are any $n$ events, then

normal

If $A$ and $B$ are two events such that $P\left( {A \cup B} \right) = P\left( {A \cap B} \right)$, then the incorrect statement amongst the following statements is

hard

(JEE MAIN-2014)

If $A$ and $B$ are two independent events such that $P(A) > 0.5,\,P(B) > 0.5,\,P(A \cap \bar B) = \frac{3}{{25}},\,P(\bar A \cap B) = \frac{8}{{25}}$ , then $P(A \cap B)$ is

normal

In two events $P(A \cup B) = 5/6$, $P({A^c}) = 5/6$, $P(B) = 2/3,$ then $A$ and $B$ are

medium