Basic Maths
medium

Frequency $f$ of a simple pendulum depends on its length $\ell$ and acceleration $g$ due to gravity according to the following equation $f=\frac{1}{2 \pi} \sqrt{\frac{ g }{\ell}}$. Graph between which of the following quantities is a straight line?

A

$f$ on the ordinate and $\ell$ on the abscissa

B

$f$ on the ordinate and $\sqrt{ \ell }$ on the abscissa

C

$f ^2$ on the ordinate and $\ell$ on the abscissa

D

$f ^2$ on the ordinate and $1 / \ell$ on the abscissa

Solution

(d)

$\because \quad f =\frac{1}{2 \pi} \sqrt{\frac{ g }{\ell}} \quad \therefore f ^2 \propto \frac{1}{\ell}$

Standard 11
Physics

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