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Frequency $f$ of a simple pendulum depends on its length $\ell$ and acceleration $g$ due to gravity according to the following equation $f=\frac{1}{2 \pi} \sqrt{\frac{ g }{\ell}}$. Graph between which of the following quantities is a straight line?
A
$f$ on the ordinate and $\ell$ on the abscissa
B
$f$ on the ordinate and $\sqrt{ \ell }$ on the abscissa
C
$f ^2$ on the ordinate and $\ell$ on the abscissa
D
$f ^2$ on the ordinate and $1 / \ell$ on the abscissa
Solution
(d)
$\because \quad f =\frac{1}{2 \pi} \sqrt{\frac{ g }{\ell}} \quad \therefore f ^2 \propto \frac{1}{\ell}$
Standard 11
Physics