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14.Probability
easy
From a group of $7$ men and $4$ ladies a committee of $6$ persons is formed, then the probability that the committee contains $2$ ladies is
A
$\frac{5}{{13}}$
B
$\frac{5}{{11}}$
C
$\frac{4}{{11}}$
D
$\frac{3}{{11}}$
Solution
(b) Total number of ways to select $6$ persons out of $11 = {}^{11}{C_6}$
Ways to select two ladies $ = {}^4{C_2}$
Ways to select four men $ = {}^7{C_4}$
$\therefore $ Probability that committee contain $2$ ladies
$ = \frac{{{}^4{C_2}.{}^7{C_4}}}{{{}^{11}{C_6}}} = \frac{5}{{11}}.$
Standard 11
Mathematics