From a newly formed radioactive substance (Ha | vedclass

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Question

(b) $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n}$

$\Rightarrow \frac{1}{{64}} = {\left( {\frac{1}{2}} \right)^6}$

$= {\left( {\frac{1}{

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(b) $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} ight)^n}$

$\Rightarrow \frac{1}{{64}} = {\left( {\frac{1}{2}} ight)^6}$

$= {\left( {\frac{1}{2}} ight)^n} \Rightarrow n = 6.$

After $6$ half lives intensity emitted will be safe.  

Total time taken $ = 6 	imes 2 = 12\,hrs.$

From a newly formed radioactive substance (Half life $2$ hours), the intensity of radiation is $64$ times the permissible safe level. The minimum time after which work can be done safely from this source is ..........$hours$

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