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Trigonometrical Equations
easy
$\tan 5\theta = \cot 2\theta $ का व्यापक हल होगा, (जहाँ $n \in Z$)
A
$\theta = \frac{{n\pi }}{7} + \frac{\pi }{{14}}$
B
$\theta = \frac{{n\pi }}{7} + \frac{\pi }{5}$
C
$\theta = \frac{{n\pi }}{7} + \frac{\pi }{2}$
D
$\theta = \frac{{n\pi }}{7} + \frac{\pi }{3}$
Solution
(a) $\tan 5\theta = \tan \left( {\frac{\pi }{2} – 2\theta } \right)$
$ \Rightarrow $ $5\theta = n\pi + \frac{\pi }{2} – 2\theta $
$ \Rightarrow $ $7\theta = n\pi + \frac{\pi }{2}$
$ \Rightarrow $ $\theta = \frac{{n\pi }}{7} + \frac{\pi }{{14}}$.
Standard 11
Mathematics
