Give reason : ''Small and light pieces of paper are attracted by comb run through dry hair.&

English

Gujarati

Hindi

1. Electric Charges and Fields

medium

Give reason : ''Small and light pieces of paper are attracted by comb run through dry hair.''

Option A

Option B

Option C

Option D

Solution

A comb run through dry hair acquires charge through friction but the paper is not charged. The charged comb 'polarizes' the piece of paper, induces a net dipole moment in the direction of field. Further, the electric field due to the comb is not uniform. In this situation it is easily seen that the paper should move in the direction of the comb.

Standard 12

Physics

A charged water drop whose radius is $0.1\,\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be…….$N/C$ $(g = 10\,m{s^{ – 1}})$

medium

Mention characteristics of electric field.

medium

A uniformly charged rod of length $4\,m$ and linear charge density $\lambda = 30\,\mu C/m$ is placed as shown in figure. Calculate the $x-$ component of electric field at point $P$.

medium

Two charges $e$ and $3 e$ are placed at a distance $r$. The distance of the point where the electric field intensity will be zero is ………

medium

The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass and charge of an electron respectively are $9.1 \times 10^{-31}\,kg$ and $1.6 \times$ $10^{-19}\,C$.)

easy

Give reason : ''Small and light pieces of paper are attracted by comb run through dry hair.''

Solution

Similar Questions

A charged water drop whose radius is $0.1\,\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be…….$N/C$ $(g = 10\,m{s^{ – 1}})$

Mention characteristics of electric field.

A uniformly charged rod of length $4\,m$ and linear charge density $\lambda = 30\,\mu C/m$ is placed as shown in figure. Calculate the $x-$ component of electric field at point $P$.

Two charges $e$ and $3 e$ are placed at a distance $r$. The distance of the point where the electric field intensity will be zero is ………

The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass and charge of an electron respectively are $9.1 \times 10^{-31}\,kg$ and $1.6 \times$ $10^{-19}\,C$.)

Start a Free Trial Now