Given two independent events $A$ and $B$ such $P(A)$ $=0.3,\, P(B)=0.6 .$ Find $P(A$ or $B)$
Given two independent events $A$ and $B$ such $P(A)$ $=0.3,\, P(B)=0.6 .$ Find $P(A$ or $B)$
It is given that $P(A)=0.3, P(B)=0.6$
Also, $A$ and $B$ are independent events.
$P(A$ or $B)=P(A \cup B)$
$=\mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})-\mathrm{P}(\mathrm{A} \cap \mathrm{B})$
$=0.3+0.6-0.18$
$=0.72$
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$P(A)$
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........
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| $\frac {1}{3}$ | $\frac {1}{5}$ | $\frac {1}{15}$ | ........ |
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