14.Probability
easy

Given two independent events $A$ and $B$ such $P(A)$ $=0.3,\, P(B)=0.6 .$ Find $P(A$  or $B)$

A

$0.72$

B

$0.72$

C

$0.72$

D

$0.72$

Solution

It is given that $P(A)=0.3, P(B)=0.6$

Also, $A$ and $B$ are independent events.

$P(A$  or $B)=P(A \cup B)$

$=\mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})-\mathrm{P}(\mathrm{A} \cap \mathrm{B})$

$=0.3+0.6-0.18$

$=0.72$

Standard 11
Mathematics

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