Given two independent events A and B such P(A) =0.3,, P(B)=0.6 . Find P(A or B)

English

Gujarati

Hindi

14.Probability

easy

Given two independent events $A$ and $B$ such $P(A)$ $=0.3,\, P(B)=0.6 .$ Find $P(A$ or $B)$

A

$0.72$

B

$0.72$

C

$0.72$

D

$0.72$

Solution

It is given that $P(A)=0.3, P(B)=0.6$

Also, $A$ and $B$ are independent events.

$P(A$ or $B)=P(A \cup B)$

$=\mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})-\mathrm{P}(\mathrm{A} \cap \mathrm{B})$

$=0.3+0.6-0.18$

$=0.72$

Standard 11

Mathematics

Share

Similar Questions

If two events $A$ and $B$ are such that $P\,(A + B) = \frac{5}{6},$ $P\,(AB) = \frac{1}{3}\,$ and $P\,(\bar A) = \frac{1}{2},$ then the events $A$ and $B$ are

easy

In a city $20\%$ persons read English newspaper, $40\%$ read Hindi newspaper and $5\%$ read both newspapers. The percentage of non-reader either paper is

easy

Two cards are drawn at random and without replacement from a pack of $52$ playing cards. Finds the probability that both the cards are black.

medium

An integer is chosen at random from the integers $\{1,2,3, \ldots \ldots . .50\}$. The probability that the chosen integer is a multiple of atleast one of $4,6$ and $7$ is

medium

(JEE MAIN-2024)

If $A$ and $B$ are two events such that $P\,(A \cup B) = P\,(A \cap B),$ then the true relation is

medium

(IIT-1998)