How many chords can be drawn through $21$ points on a circle?
For drawing one chord a circle, only $2$ points are required.
To know the number of chords that can be drawn through the given $21$ points on a circle, the number of combinations have to be counted.
Therefore, there will be as many chords as there are combinations of $21$ points taken $2$ at a time.
Thus, required number of chords $=\,^{21} C_{2}=\frac{21 !}{2 !(21-2) !}=\frac{21 !}{2 ! 19 !}=\frac{21 \times 20}{2}=210$
Let $A_1,A_2,........A_{11}$ are players in a team with their T-shirts numbered $1,2,.....11$. Hundred gold coins were won by the team in the final match of the series. These coins is to be distributed among the players such that each player gets atleast one coin more than the number on his T-shirt but captain and vice captain get atleast $5$ and $3$ coins respectively more than the number on their respective T-shirts, then in how many different ways these coins can be distributed ?
Value of $r$ for which $^{15}{C_{r + 3}} = {\,^{15}}{C_{2r - 6}}$ is
A committee of $11$ members is to be formed from $8$ males and $5$ females. If $m$ is the number of ways the committee is formed with at least $6$ males and $n$ is the number of ways the committee is formed with at least $3$ females, then
If $^n{C_{12}} = {\,^n}{C_6}$, then $^n{C_2} = $
If $^n{P_r} = 840,{\,^n}{C_r} = 35,$ then $n$ is equal to