Identify correct statement among following

Gujarati

Hindi

13.Oscillations

easy

Identify correct statement among the following

The greater the mass of a pendulum bob, the shorter is its frequency of oscillation

A simple pendulum with a bob of mass M swings with an angular amplitude of ${40^o}$. When its angular amplitude is ${20^o}$, the tension in the string is less than $Mg\cos {20^o}$.

As the length of a simple pendulum is increased, the maximum velocity of its bob during its oscillation will also decreases

The fractional change in the time period of a pendulum on changing the temperature is independent of the length of the pendulum

Solution

(c)

Standard 11

Physics

One-forth length of a spring of force constant $K$ is cut away. The force constant of the remaining spring will be

medium

Two masses $m_1$ and $m_2$ connected by a spring of spring constant $k$ rest on a frictionless surface. If the masses are pulled apart and let go, the time period of oscillation is

hard

(KVPY-2010)

The force-deformation equation for a nonlinear spring fixed at one end is $F =4x^{1/ 2}$ , where $F$ is the force (expressed in newtons) applied at the other end and $x$ is the deformation expressed in meters

hard

The springs in figure. $A$ and $B$ are identical but length in $A$ is three times that in $B$. The ratio of period $T_A/T_B$ is

medium

A weightless spring which has a force constant oscillates with frequency $n$ when a mass $m$ is suspended from it. The spring is cut into two equal halves and a mass $2m $ is suspended from it. The frequency of oscillation will now become

medium

Identify correct statement among the following

Solution

Similar Questions

One-forth length of a spring of force constant $K$ is cut away. The force constant of the remaining spring will be

Two masses $m_1$ and $m_2$ connected by a spring of spring constant $k$ rest on a frictionless surface. If the masses are pulled apart and let go, the time period of oscillation is

The force-deformation equation for a nonlinear spring fixed at one end is $F =4x^{1/ 2}$ , where $F$ is the force (expressed in newtons) applied at the other end and $x$ is the deformation expressed in meters

The springs in figure. $A$ and $B$ are identical but length in $A$ is three times that in $B$. The ratio of period $T_A/T_B$ is

A weightless spring which has a force constant oscillates with frequency $n$ when a mass $m$ is suspended from it. The spring is cut into two equal halves and a mass $2m $ is suspended from it. The frequency of oscillation will now become

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