यदि $\Delta_{1}=\left|\begin{array}{ccc} x & \sin \theta & \cos \theta \\ -\sin \theta & - x & 1 \\ \cos \theta & 1 & x \end{array}\right|$ तथा $\Delta_{2}=\left|\begin{array}{ccc}x & \sin 2 \theta & \cos 2 \theta \\ -\sin 2 \theta & -x & 1 \\ \cos 2 \theta & 1 & x\end{array}\right|, x \neq 0$; तो सभी $\theta \in\left(0, \frac{\pi}{2}\right)$ के लिए
${\Delta _1} - {\Delta _2} = - 2{x^3}$
${\Delta _1} + {\Delta _2} = - 2({x^3} + x - 1)$
${\Delta _1} - {\Delta _2} = x\left( {\cos \,2\theta - \cos \,4\theta } \right)$
${\Delta _1} + {\Delta _2} = - 2{x^3}$
यदि $\left| {{\kern 1pt} \begin{array}{*{20}{c}}1&2&3\\2&x&3\\3&4&5\end{array}\,} \right| = 0,$ तो $x =$
निकाय $x + y + z = \lambda ,$ $5x - y + \mu z = 10$, $2x + 3y - z = 6$ के अद्वितीय हल का अस्तित्व निर्भर करता है
यदि $a_{r}=\cos \frac{2 r \pi}{9}+i \sin \frac{2 r \pi}{9}, \quad r=1,2,3, \ldots$, $i=\sqrt{-1}$, तो सारणिक $\left|\begin{array}{lll}a_{1} & a_{2} & a_{3} \\ a_{4} & a_{5} & a_{6} \\ a_{7} & a_{8} & a_{9}\end{array}\right|$ बराबर है
$\left| {\,\begin{array}{*{20}{c}}{{a_1}}&{m{a_1}}&{{b_1}}\\{{a_2}}&{m{a_2}}&{{b_2}}\\{{a_3}}&{m{a_3}}&{{b_3}}\end{array}\,} \right| = $
यदि $\Delta = \left| {\,\begin{array}{*{20}{c}}a&{a + b}&{a + b + c}\\{3a}&{4a + 3b}&{5a + 4b + 3c}\\{6a}&{9a + 6b}&{11a + 9b + 6c}\end{array}\,} \right|$ जहाँ $a = i,b = \omega ,c = {\omega ^2}$, तब $\Delta $का मान होगा