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4-1.Complex numbers
normal
If $arg\, z < 0$ then $arg\, (-z)\, -arg(z)$ is equal to
A
$\pi $
B
$-\pi $
C
$-\frac {\pi }{2}$
D
$\frac {\pi }{2}$
Solution
$\because \arg (z)<0$
$\because \arg (z)-\arg (-z)=-\pi$
Hence, $\arg (-\mathrm{z})-\arg (\mathrm{z})=\pi$
Standard 11
Mathematics