Gujarati
Hindi
4-1.Complex numbers
normal

If $arg\, z < 0$ then $arg\, (-z)\, -arg(z)$ is equal to

A

$\pi $

B

$-\pi $

C

$-\frac {\pi }{2}$

D

$\frac {\pi }{2}$

Solution

$\because \arg (z)<0$

$\because \arg (z)-\arg (-z)=-\pi$

Hence, $\arg (-\mathrm{z})-\arg (\mathrm{z})=\pi$

Standard 11
Mathematics

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