Conjugate of complex number frac{{2 - 3i}}{{4

English

Gujarati

Hindi

4-1.Complex numbers

easy

The conjugate of complex number $\frac{{2 - 3i}}{{4 - i}},$ is

$\frac{{3i}}{4}$

$\frac{{11 + 10i}}{{17}}$

$\frac{{11 - 10i}}{{17}}$

$\frac{{2 + 3i}}{{4i}}$

Solution

(b) $\frac{{2 – 3i}}{{4 – i}} = \frac{{(2 – 3i)\,(4 + i)}}{{(4 + i)\,(4 – i)}}$$ = \frac{{8 + 3 – 12i + 2i}}{{16 + 1}}$$ = \,\frac{{11 – 10i}}{{17}}$
==> Conjugate $ = \frac{{11 + 10i}}{{17}}$.

Standard 11

Mathematics

Let $S=\left\{Z \in C: \bar{z}=i\left(z^2+\operatorname{Re}(\bar{z})\right)\right\}$. Then $\sum_{z \in S}|z|^2$ is equal to

hard

(JEE MAIN-2023)

If $|z – 25i| \le 15$, then $|\max .amp(z) – \min .amp(z)| = $

hard

Conjugate of $1 + i$ is

normal

If $z$ is a complex number, then which of the following is not true

normal

If $z$ is a complex number such that $| z | = 4$ and $arg \,(z) = \frac {5\pi }{6}$ , then $z$ is equal to

normal

The conjugate of complex number $\frac{{2 - 3i}}{{4 - i}},$ is

Solution

Similar Questions

Let $S=\left\{Z \in C: \bar{z}=i\left(z^2+\operatorname{Re}(\bar{z})\right)\right\}$. Then $\sum_{z \in S}|z|^2$ is equal to

If $|z – 25i| \le 15$, then $|\max .amp(z) – \min .amp(z)| = $

Conjugate of $1 + i$ is

If $z$ is a complex number, then which of the following is not true

If $z$ is a complex number such that $| z | = 4$ and $arg \,(z) = \frac {5\pi }{6}$ , then $z$ is equal to

Start a Free Trial Now