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4-1.Complex numbers
normal
The value of $|z - 5|$if $z = x + iy$, is
A
$\sqrt {{{(x - 5)}^2} + {y^2}} $
B
${x^2} + \sqrt {{{(y - 5)}^2}} $
C
$\sqrt {{{(x - y)}^2} + {5^2}} $
D
$\sqrt {{x^2} + {{(y - 5)}^2}} $
Solution
(a)$z = x + iy$, then $|z – 5|\, = \,|x + iy – 5|\, = \,|x – 5 + iy|$
$ = \sqrt {{{(x – 5)}^2} + {y^2}} $.
Standard 11
Mathematics