If $(p \wedge \sim q) \wedge r \to \sim r$ is $F$ then truth value of $'r'$ is :-
If $(p \wedge \sim q) \wedge r \to \sim r$ is $F$ then truth value of $'r'$ is :-
- A
$T$
- B
$F$
- C
Can't say
- D
May be $'T'$ or may be $'F'$
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- [JEE MAIN 2019]
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Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.
Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.