Let Delta in{wedge, vee, Rightarrow, Leftrigh | vedclass

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Question

$p \vee q \Rightarrow q$

$\Rightarrow \sim( p \vee q ) \vee q$

$\Rightarrow(\sim p \wedge \sim q ) \vee q$

$\Rightarrow(\sim p \vee q ) \wedg

Vedclass · Accepted Answer

$\Rightarrow$

Vedclass · Answer

$p \vee q \Rightarrow q$

$\Rightarrow \sim( p \vee q ) \vee q$

$\Rightarrow(\sim p \wedge \sim q ) \vee q$

$\Rightarrow(\sim p \vee q ) \wedge(\sim q \vee q )$

$\Rightarrow(\sim p \vee q ) \wedge t =\sim p \vee q$

Now by taking option $C$

$( p \wedge q ) \Rightarrow \sim p \vee q$

$\Rightarrow \sim p \vee \sim q \vee \sim p \vee q$

$\Rightarrow t$

Hence $C$

Let $\Delta \in\{\wedge, \vee, \Rightarrow, \Leftrightarrow\}$ be such that $(p \wedge q) \Delta((p \vee q) \Rightarrow q)$ is a tautology. Then $\Delta$ is equal to

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