જો $A + B + C = \frac{\pi }{2}$ થાય તો $tanA\,\, tanB + tanB\,\, tanC + tanC\,\, tanA$ =
$0$
$tanA\,\, tanB\,\, tanC$
$1$
$-1$
જો $\tan A = \frac{1}{2},$ તો $\tan 3A = $
$\frac{{3 + \cot \,7\,{6^ \circ }\,\cot \,{{16}^ \circ }}}{{\cot \,{{76}^ \circ } + \cot \,{{16}^ \circ }}}$ =
$\cos 15^\circ - \sin 15^\circ = . . .$
$\frac{{3 + \cot {{76}^o}\cot {{16}^o}}}{{\cot {{76}^o} + \cot {{16}^o}}}$ =
સાબિત કરો કે, $\tan 3 x \tan 2 x \tan x=\tan 3 x-\tan 2 x-\tan x$