3.Trigonometrical Ratios, Functions and Identities
easy

જો $\cos A = \frac{3}{4}$, તો $32\sin \frac{A}{2}\cos \frac{5}{2}A = $

A

$\sqrt 7 $

B

$ - \sqrt 7 $

C

$7$

D

$-7$

Solution

(b) $\cos A = \frac{3}{4} \Rightarrow \sin A = \frac{{\sqrt 7 }}{4}$

$L.H.S.$ $ = 16(\sin 3A – \sin 2A)$

$ = 16\sin A(3 – 4{\sin ^2}A – 2\cos A)$

$ = 16.\frac{{\sqrt 7 }}{4}\left( {3 – 4.\frac{7}{{16}} – 2.\frac{3}{4}} \right) = – \sqrt 7 $.

Standard 11
Mathematics

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