8. Sequences and Series
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જો $a_1, a_2, a_3 …………$ એ સમાંતર શ્રેણીમાં છે અને $a_1 + a_4 + a_7 + …………… + a_{16} = 114$, હોય તો  $a_1 + a_6 + a_{11} + a_{16}$ ની કિમંત મેળવો.

A

$76$

B

$64$

C

$98$

D

$38$

(JEE MAIN-2019)

Solution

${a_1} + {a_4} + {a_{  7}} + {a_{10}} + {a_{13}} + {a_{16}} = 114$

$ \Rightarrow \frac{6}{2}\left( {{a_1} + {a_{16}}} \right) = 114$

${a_1} + {a_{16}} = 38$

So, ${a_1} + {a_6} + {a_{  11}} + {a_{16}} = \frac{4}{2}\left( {{a_1} + {a_{16}}} \right)$

$ = 2 \times 38 \Rightarrow 76$

Standard 11
Mathematics

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