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1.Set Theory
easy
If $X$ and $Y$ are two sets such that $n( X )=17, n( Y )=23$ and $n( X \cup Y )=38$
find $n( X \cap Y )$
A
$2$
B
$2$
C
$2$
D
$2$
Solution
It is given that:
$n(X)=17, n(Y)=23, n(X \cup Y)=38$
We know that:
$n(X \cup Y)=n(X)+n(Y)-n(X \cap Y)$
$\therefore 38=17+23-n(X \cap Y)$
$\Rightarrow n(X \cap Y)=40-38=2$
$\therefore n(X \cap Y)=2$
Standard 11
Mathematics
