If $n(A) = 3$, $n(B) = 6$ and $A \subseteq B$. Then the number of elements in $A \cup B$ is equal to
$3$
$9$
$6$
None of these
(c) Since $A \subseteq B,\,\,\,\therefore A \cup B = B$
So, $n(A \cup B) = n(B) = 6$.
If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find
$A-B$
If $A, B$ and $C$ are any three sets, then $A -(B \cup C)$ is equal to
If $A$ and $B$ are any two sets, then $A \cap (A \cup B)$ is equal to
Let $A :\{1,2,3,4,5,6,7\}$. Define $B =\{ T \subseteq A$ : either $1 \notin T$ or $2 \in T \}$ and $C = \{ T \subseteq A : T$ the sum of all the elements of $T$ is a prime number $\}$. Then the number of elements in the set $B \cup C$ is $\dots\dots$
If $A$ and $B$ are disjoint, then $n(A \cup B)$ is equal to
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