If $x+\frac{1}{x}=a, x^2+\frac{1}{x^3}=b$, then $x^3+\frac{1}{x^2}$ is

  • [KVPY 2011]
  • A

    $a^3+a^2-3 a-2-b$

  • B

    $a^3-a^2-3 a+4-b$

  • C

    $a^3-a^2+3 a-6-b$

  • D

    $a^3+a^2+3 a-16-b$

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