If $\vec{P}+\vec{Q}=\vec{P}-\vec{Q}$, then

  • A

    $\vec{P}=\overrightarrow{0}$

  • B

    $\vec{Q}=\overrightarrow{0}$

  • C

    $|\vec{P}|=1$

  • D

    $|\vec{Q}|=1$

Similar Questions

Statement $I :$Two forces $(\overrightarrow{{P}}+\overrightarrow{{Q}})$ and $(\overrightarrow{{P}}-\overrightarrow{{Q}})$ where $\overrightarrow{{P}} \perp \overrightarrow{{Q}}$, when act at an angle $\theta_{1}$ to each other, the magnitude of their resultant is $\sqrt{3\left({P}^{2}+{Q}^{2}\right)}$, when they act at an angle $\theta_{2}$, the magnitude of their resultant becomes $\sqrt{2\left({P}^{2}+{Q}^{2}\right)}$. This is possible only when $\theta_{1}<\theta_{2}$.

Statement $II :$ In the situation given above. $\theta_{1}=60^{\circ} \text { and } \theta_{2}=90^{\circ}$ In the light of the above statements, choose the most appropriate answer from the options given below

  • [JEE MAIN 2021]

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