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Mathematical Reasoning
hard
If $p , q$ and $r$ are three propositions, then which of the following combination of truth values of $p , q$ and $r$ makes the logical expression $\{(p \vee q) \wedge((\sim p) \vee r)\} \rightarrow((\sim q) \vee r)$ false ?
A
$p = T , q = F , r = T$
B
$p = T , q = T , r = F$
C
$p = F , q = T , r = F$
D
$p = T , q = F , r = F$
(JEE MAIN-2023)
Solution
Option $(3)(p \vee q) \wedge(\sim q \vee r) \rightarrow(\sim p \vee r)$ will be False.
Standard 11
Mathematics
