If $A$ and $B$ are any two sets, then $A \cup (A \cap B) $ is equal to
$A$
$B$
${A^c}$
${B^c}$
(a) $A \cap B \subseteq A$. Hence $A \cup (A \cap B) = A$.
If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find
$A \cap D$
If $A$ and $B$ are any two sets, then $A \cap (A \cup B)$ is equal to
Let $A :\{1,2,3,4,5,6,7\}$. Define $B =\{ T \subseteq A$ : either $1 \notin T$ or $2 \in T \}$ and $C = \{ T \subseteq A : T$ the sum of all the elements of $T$ is a prime number $\}$. Then the number of elements in the set $B \cup C$ is $\dots\dots$
Show that if $A \subset B,$ then $(C-B) \subset( C-A)$
If $aN = \{ ax:x \in N\} $ and $bN \cap cN = dN$, where $b$, $c \in N$ are relatively prime, then
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