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1.Set Theory
easy
If $A$ and $B$ are two given sets, then $A \cap {(A \cap B)^c}$ is equal to
A
$A$
B
$B$
C
$\phi $
D
$A \cap {B^c}$
Solution
(d) $A \cap {(A \cap B)^c} = A \cap ({A^c} \cup {B^c})$
= $(A \cap {A^c}) \cup (A \cap {B^c})$ = $\phi \cup (A \cap {B^c}) = A \cap {B^c}$.
Standard 11
Mathematics