If $A$ is any set, then
$A \cup A' = \phi $
$A \cup A' = U$
$A \cap A' = U$
None of these
(b) It is obvious.
If $n(U)$ = $600$ , $n(A)$ = $100$ , $n(B)$ = $200$ and $n(A \cap B )$ = $50$, then $n(\bar A \cap \bar B )$ is
($U$ is universal set and $A$ and $B$ are subsets of $U$)
Let $U=\{1,2,3,4,5,6\}, A=\{2,3\}$ and $B=\{3,4,5\}$
Find $A^{\prime}, B^{\prime}, A^{\prime} \cap B^{\prime}, A \cup B$ and hence show that $(A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}$
If $U =\{1,2,3,4,5,6,7,8,9\}, A =\{2,4,6,8\}$ and $B =\{2,3,5,7\} .$ Verify that
$(A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}$
Taking the set of natural numbers as the universal set, write down the complements of the following sets:
$\{ x:x$ is a natural number divisible by $ 3 $ and $5\} $
If $U=\{a, b, c, d, e, f, g, h\},$ find the complements of the following sets:
$A=\{a, b, c\}$
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