If $A$ and $B$ are not disjoint sets, then $n(A \cup B)$ is equal to
$n(A) + n(B)$
$n(A) + n(B) - n(A \cap B)$
$n(A) + n(B) + n(A \cap B)$
$n(A)\,n(B)$
(b) $n(A \cup B) = n(A) + n\,(B) – n(A \cap B)$.
If $A=\{1,2,3,4\}, B=\{3,4,5,6\}, C=\{5,6,7,8\}$ and $D=\{7,8,9,10\} ;$ find
$B \cup D$
If $A = \{ x:x$ is a natural number $\} ,B = \{ x:x$ is an even natural number $\} $ $C = \{ x:x$ is an odd natural number $\} $ and $D = \{ x:x$ is a prime number $\} ,$ find $B \cap C$
If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find
$D-A$
Show that $A \cup B=A \cap B$ implies $A=B$.
Let $A$ and $B$ be sets. If $A \cap X=B \cap X=\phi$ and $A \cup X=B \cup X$ for some set $X ,$ show that $A = B$
( Hints $A = A \cap (A \cup X),B = B \cap (B \cup X)$ and use Distributive law )
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