If x = {log _a}(bc),y = {log _b}(ca),z = {log | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $x = {\log _a}bc$  $ \Rightarrow $ $1 + x = {\log _a}a + {\log _a}bc = {\log _a}abc$

$	herefore {(1 + x)^{ - 1}} = {\log _{abc}}a$

$

Vedclass · Accepted Answer

${(1 + x)^{ - 1}} + {(1 + y)^{ - 1}} + {(1 + z)^{ - 1}}$

Vedclass · Answer

(b) $x = {\log _a}bc$  $ \Rightarrow $ $1 + x = {\log _a}a + {\log _a}bc = {\log _a}abc$

$	herefore {(1 + x)^{ - 1}} = {\log _{abc}}a$

$	herefore {(1 + x)^{ - 1}} + {(1 + y)^{ - 1}} + {(1 + z)^{ - 1}} = {\log _{abc}}a + {\log _{abc}}b + {\log _{abc}}c$

$ = {\log _{abc}}abc = 1$.

If $x = {\log _a}(bc),y = {\log _b}(ca),z = {\log _c}(ab),$then which of the following is equal to $1$

Similar Questions

The sum $\sum \limits_{n=1}^{\infty} \frac{2 n^2+3 n+4}{(2 n) !}$ is equal to :

The number of solution pairs $(x, y)$ of the simultaneous equations $\log _{1 / 3}(x+y)+\log _3(x-y)=2$ $2^{y^2}=512^{x+1}$ is

If ${\log _{10}}2 = 0.30103,{\log _{10}}3 = 0.47712,$ the number of digits in ${3^{12}} \times {2^8} $ is

The number of solution $(s)$ of the equation $log_7(2^x -1) + log_7(2^x -7) = 1$, is -

$\sum\limits_{r = 1}^{89} {{{\log }_3}(\tan \,\,{r^o})} = $