If {log _{10}}2 = 0.30103,{log _{10}}3 = 0.47 | vedclass

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(c) $y = {3^{12}} 	imes {2^8}$ $ \Rightarrow $ ${\log _{10}}y = 12{\log _{10}}3 + 8{\log _{10}}2$

$ = 12 	imes 0.47712 + 8 	imes 0.30103$

$ =

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(c) $y = {3^{12}} 	imes {2^8}$ $ \Rightarrow $ ${\log _{10}}y = 12{\log _{10}}3 + 8{\log _{10}}2$

$ = 12 	imes 0.47712 + 8 	imes 0.30103$

$ = 5.72544 + 2.40824 = 8.13368$

$	herefore$ Number of digits in $y$ $= 8 + 1 = 9.$

If ${\log _{10}}2 = 0.30103,{\log _{10}}3 = 0.47712,$ the number of digits in ${3^{12}} \times {2^8} $ is

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