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Basic of Logarithms
medium
જો ${\log _{10}}2 = 0.30103,{\log _{10}}3 = 0.47712$ તો ${3^{12}} \times {2^8}$ માં રહેલા અંકોની સંખ્યા મેળવો.
A
$7$
B
$8$
C
$9$
D
$10$
Solution
(c) $y = {3^{12}} \times {2^8}$ $ \Rightarrow $ ${\log _{10}}y = 12{\log _{10}}3 + 8{\log _{10}}2$
$ = 12 \times 0.47712 + 8 \times 0.30103$
$ = 5.72544 + 2.40824 = 8.13368$
$\therefore$ Number of digits in $y$ $= 8 + 1 = 9.$
Standard 11
Mathematics
