If ${1 \over 2} \le {\log _{0.1}}x \le 2$ then
The maximum value of $x$ is $1/\sqrt {10} $
$x$ lies between $1/100$ and $1/\sqrt {10} $
The minimum value of $x$ is $1/100$
All of These
Solution set of inequality ${\log _{10}}({x^2} - 2x - 2) \le 0$ is
If ${\log _{0.04}}(x - 1) \ge {\log _{0.2}}(x - 1)$ then $x$ belongs to the interval
$\log ab - \log |b| = $
If $x = {\log _a}(bc),y = {\log _b}(ca),z = {\log _c}(ab),$then which of the following is equal to $1$
The number ${\log _2}7$ is