If $a = \sqrt {(21)} - \sqrt {(20)} $ and $b = \sqrt {(18)} - \sqrt {(17),} $ then
$a = b$
$a + b = 0$
$a > b$
$a < b$
The value of ${{15} \over {\sqrt {10} + \sqrt {20} + \sqrt {40} - \sqrt 5 - \sqrt {80} }}$ is
Number of Solution of the equation ${(x)^{x\sqrt x }} = {(x\sqrt x )^x}$ are
If $x + \sqrt {({x^2} + 1)} = a,$ then $x =$
$\sqrt {(3 + \sqrt 5 )} $ is equal to
If ${a^x} = bc,{b^y} = ca,\,{c^z} = ab,$ then $xyz$=