Number of Solution of the equation {(x)^{xsqr | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) ${x^{x\sqrt x }} = {(x\sqrt x )^x} \Rightarrow {x^{{x^{3/2}}}} = {({x^{3/2}})^x}$

$ \Rightarrow $${x^{{x^{3/2}}}} = {x^{(3/2)x}}$

$ \Rightar

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(b) ${x^{x\sqrt x }} = {(x\sqrt x )^x} \Rightarrow {x^{{x^{3/2}}}} = {({x^{3/2}})^x}$

$ \Rightarrow $${x^{{x^{3/2}}}} = {x^{(3/2)x}}$

$ \Rightarrow $${x^{3/2}} = {3 \over 2}x$ $ \Rightarrow $${x^{1/2}} = {3 \over 2}$

$ \Rightarrow $$x = {9 \over 4}$

Also $x = 1$ is an obvious solution.

Number of Solution of the equation ${(x)^{x\sqrt x }} = {(x\sqrt x )^x}$ are

Similar Questions

Solution of the equation ${9^x} - {2^{x + {1 \over 2}}} = {2^{x + {3 \over 2}}} - {3^{2x - 1}}$

If $x = 3 - \sqrt {5,} $ then ${{\sqrt x } \over {\sqrt 2 + \sqrt {(3x - 2)} }} = $

If ${a^x} = bc,{b^y} = ca,\,{c^z} = ab,$ then $xyz$=

The value of $\sqrt {[12 - \sqrt {(68 + 48\sqrt 2 )} ]} = $

If ${({a^m})^n} = {a^{{m^n}}}$, then the value of $'m'$ in terms of $'n'$ is