If z is a purely real number such that {mathop{rm Re}nolimits} (z) < 0 , then arg(z) is equal to

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4-1.Complex numbers

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If $z$ is a purely real number such that ${\mathop{\rm Re}\nolimits} (z) < 0$, then $arg(z)$ is equal to

A

$\pi $

B

$\frac{\pi }{2}$

C

$0$

D

$ - \frac{\pi }{2}$

Solution

(a)Let $z = a + i0$, where $a < 0$. Then $z$ is represented by a point on negative side of $x$-axis, therefore $arg(z) = \pi $

Standard 11

Mathematics

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